[Leetcode - Easy] Number of Different Integers in a String

suhwan2004/Number of Different Integers in a String.js

@@ -0,0 +1,39 @@
+/*
+22:39 ~ 22:47
+
+Time : O(N)
+Space : O(N)
+ALGO : for
+DS : hash Set, String
+Constraints
+- 1 <= word.length <= 1000
+- 주어지는 word는 숫자와 영소문자로 구성된다
+Edge Case : X
+*/
+var numDifferentIntegers = function(word) {
+    let set = new Set()
+    let curDigit = ''
+
+    for(let i = 0; i < word.length; i++){
+        const curC = word[i]
+        const nextC = word[i+1]
+        if(curC >= 'a' && curC <= 'z'){
+            if(curDigit){
+                set.add(curDigit)
+                curDigit = ''
+            }
+        }else if(curDigit === '' && curC === '0') {
+            if(i === word.length-1 || (nextC >= 'a' && nextC <= 'z')) curDigit += curC
+            else continue;
+        }else {
+            curDigit += curC
+        }
+    }
+
+    if(curDigit){
+        set.add(curDigit)
+        curDigit = ''
+    }
+
+    return set.size
+};